0.6x+9=x^2-4

Solution for 0.6x+9=x^2-4 equation:

0.6x+9=x^2-4

We move all terms to the left:

0.6x+9-(x^2-4)=0

We get rid of parentheses

-x^2+0.6x+4+9=0

We add all the numbers together, and all the variables

-1x^2+0.6x+13=0

a = -1; b = 0.6; c = +13;
Δ = b2-4ac
Δ = 0.62-4·(-1)·13
Δ = 52.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{52.36}}{2*-1}=\frac{-0.6-\sqrt{52.36}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{52.36}}{2*-1}=\frac{-0.6+\sqrt{52.36}}{-2}
$